Stability of the species Li 2- Li 2-and Li 2-increases in the order-A- Li 2- Li 2- Li 2-B- Li 2- Li 2- Li 2C- Li 2- Li 2- Li 2-D- Li 2- Li 2- Li 2-

The correct option is B Li_2^ lt; Li_2^+ lt;Li_2Li_2 ⇒σ 1s^2 σ^* 1s^2 σ 2s^2 ∴ B.O = N_b N_A2 = 4 22 = 1 Li^+_2 ⇒σ 1s^2 σ^* 1s^2 σ 2s^1 ∴ BO = 3 22 = 12 ...

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Byju's Answer

Standard XII

Chemistry

Molecular Orbital Energy Diagrams

Stability of ...

Question

Stability of the species $L i_{2}$ , $L i_{2}^{-}$ and $L i_{2}^{+}$ increases in the order:

L i_{2} < L i_{2}^{+} < L i_{2}^{-}

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L i_{2}^{-} < L i_{2}^{+} < L i_{2}

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L i_{2} < L i_{2}^{-} < L i_{2}^{+}

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L i_{2}^{-} < L i_{2} < L i_{2}^{+}

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Solution

The correct option is B $L i_{2}^{-} < L i_{2}^{+} < L i_{2}$
$L i_{2} \Rightarrow σ 1 s^{2} σ^{} 1 s^{2} σ 2 s^{2}$
$∴ B . O = \frac{N_{b} - N_{A}}{2} = \frac{4 - 2}{2} = 1$

$L i_{2}^{+} \Rightarrow σ 1 s^{2} σ^{} 1 s^{2} σ 2 s^{1}$ $∴ B O = \frac{3 - 2}{2} = \frac{1}{2} = 0.5$

$L i_{2}^{-} \Rightarrow σ 1 s^{2} σ^{} 1 s^{2} σ 2 s^{2} σ^{} 2 s^{1}$ $∴ B . O = \frac{4 - 3}{2} = \frac{1}{2} = 0.5$

Stability order is $L i_{2}^{-} < L i_{2}^{+} < L i_{2}$ as $L i_{2}^{-}$ has more electrons in the antibonding orbitals which destabilises the species.

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Stability of the species Li2, Li−2 and Li+2 increases in the order:

Stability of the species $L i_{2}$ , $L i_{2}^{-}$ and $L i_{2}^{+}$ increases in the order: