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Byju's Answer
Standard XII
Chemistry
Gibb's Energy and Nernst Equation
Standard elec...
Question
Standard electrode potentials are Fe2+/Fe; E° = -0.44 volts Fe3+/Fe2+; E° = 0.77 volts Fe2+, Fe3+ and Fe blocks are kept together, then (1) Fe2+ increases (2) Fe3+ decreases (3) Fe2+/Fe3+ remains unchanged (4) Fe2+ decreases
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Similar questions
Q.
Given
E
⊖
F
e
2
+
|
F
e
and
E
⊖
F
e
3
+
|
F
e
2
+
are -0.44 and 0.77 V respectively.
If
F
e
2
+
,
F
e
3
+
, and
F
e
blocks are kept together, then:
Q.
Standard electrode potentials are:
F
e
2
+
/
F
e
(
E
o
=
−
0.44
V
)
,
F
e
3
+
/
F
e
2
+
(
E
o
=
0.77
V
)
F
e
2
+
,
F
e
3
+
and
F
e
blocks are kept together, then:
Q.
Standard electrode potential of two half-reactions are given below:
F
e
2
+
⇌
F
e
;
E
∘
=
−
0.44
V
F
e
3
+
⇌
F
e
2
+
;
E
∘
=
+
0.77
V
If
F
e
2
+
,
F
e
3
+
and
F
e
are kept together :
Q.
Given, standard electrode potentials:
F
e
3
+
+
3
e
−
→
F
e
;
E
∘
=
−
0.036
v
o
l
t
F
e
2
+
+
2
e
−
→
F
e
;
E
∘
=
−
0.440
v
o
l
t
The standard electrode potential
E
∘
for
F
e
3
+
+
e
−
→
F
e
2
+
is:
Q.
Given that:
E
∘
F
e
2
+
/
F
e
=
−
0.44
V
and
E
∘
F
e
3
+
/
F
e
2
+
=
0.77
V
E
∘
F
e
3
+
/
F
e
is:
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