Standard electrode potentials of Fe2++2e−→Fe and Fe3++3e−→Fe are −0.440V and −0.036V respectively. The standard electrode potential (Eo) for Fe3++e−→Fe2+ is:
A
−0.476V
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B
−0.404V
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C
+0.404V
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D
+0.772V
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Solution
The correct option is D+0.772V
Fe2++2e−→FeE01=−0.440V ......(1)
Fe3++3e−→FeE02=−0.036V ......(2)
we know that ΔG0=−nFE0cell
to obtain the resultant equation, (2)−(1)
that is-Fe3++e−→Fe2+
ΔG0net=ΔG2−ΔG1
which gives :
−nFE0net=−n2FE02−(−n1FE01)
n2=3
n1=2 For the resultant equation, n=1
Putting all the equation in the above obtained equation for the net Gibbs free energy we get,