The correct option is D the standard molar enthalpy of combustion of carbon (graphite)
Standard molar heat enthalpy (H∘) of a compound is equal to its standard heat of formation from most stable states of initial components.
Hence, standard molar enthalpy of formation of CO2 is equal to the standard molar enthalpy of combustion of carbon (graphite).
C(g)+O2(g)→CO2(g)
The above reaction can be regarded as the reaction for the combustion of carbon (graphite).
Same reaction can also be regarded as the reaction for the formation of carbon dioxide.