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Question

Standard reduction electrode potentials of three metals A,B and C are +0.5V,−3.0V & −1.2V respectively.
The decreasing order of reducing powers of these metals is:

A
A>B>C
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B
C>B>A
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C
A>C>B
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D
B>C>A
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Solution

The correct option is D B>C>A
Higher the standard reduction potential (SRP) of the metal, more is the tendency of that metal to get reduced, and hence lower is its reducing power.
Order of SRP:
A>C>B
So, the order of reducing power is B>C>A.
Hence, Option (d) is correct.

Theory: Electrochemical Series
Half-Reaction Standard Reduction Potential E (at 298 K)
F2(g)+2e2F(aq) +2.87 V
MnO4(aq)+8H+(aq)+5eMn2+(aq)+4H2O(l)
+1.51 V
Au3+(aq)+3eAu(s) +1.4 V
2Hg2+(aq)+2eHg2+(aq) +0.92 V
Ag+(aq)+eAg(s) +0.8 V
Cu2+(aq)+2eCu(s) +0.34 V
2H+(aq)+2eH2(g) 0 V
Pb2+(aq)+2ePb(s) 0.13 V
Sn2+(aq)+2eSn(s) 0.14 V
Ni2+(aq)+2eNi(s) 0.25 V
Fe2+(aq)+2eFe(s) 0.44 V
Zn2+(aq)+2eZn(s) 0.76 V
Al3+(aq)+3eAl(s) 1.66 V
Mg2+(aq)+2eMg(s) 2.36 V
Na+(aq)+eNa(s) 2.71 V
Ca2+(aq)+2eCa(s) 2.87 V
K+(aq)+eK(s) 2.93 V
Li+(aq)+eLi(s) 3.05 V

Down the table, as the SRP decreases, the reducing power increases.

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