Standard reduction potential values for the electrodes are given below Mg2- - 2e- - Mg- E0 - -2-37 V Zn2- - 2e- - Zn- E0 - -0-76 V Fe2- - 2e- - Fe- E0 - -0-44 VWhich of the following statements is correct-

You visited us 3 times! Enjoying our articles? Unlock Full Access!

Electrode Potential

Standard redu...

Question

Standard reduction potential values for the electrodes are given below
$M g^{2 +} + 2 e^{-} \to M g; E^{0} = - 2.37 V$
$Z n^{2 +} + 2 e^{-} \to Z n; E^{0} = - 0.76 V$
$F e^{2 +} + 2 e^{-} \to F e; E^{0} = - 0.44 V$
Which of the following statements is correct?

Zinc will reduce

F e^{2 +}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Zinc will reduce

M g^{2 +}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Mg oxidizes Fe

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Zinc oxidizes Fe

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B Zinc will reduce $F e^{2 +}$
$Z i n c$ will reduce $F e^{2 +}$ as zinc has more negative standard reduction potential than $i r o n$ . More negative standard reduction potential means $z i n c$ is stronger reducing agent than $i r o n$ .

Suggest Corrections

Similar questions

Q. Reduction potential for the following half/cell reaction are

Z n \to Z n^{2 +} + 2 e^{-} (E_{(Z n^{2 +} / Z n)}^{0} = - 0.76 V)

F e \to F e^{2 +} + 2 e^{-} E^{0} = 0.41 V

The EMF for the cell reaction

F e^{2 +} + Z n \to Z n^{2 +} + F e

will

Standard reduction potential values for the electrodes are given below.

$M g^{2 +} + 2 e^{-} \to M g;$ $E_{r e d}^{o} =$ $- 2.37$ V

$Z n^{2 +} + 2 e^{-} \to Z n;$ $E_{r e d}^{o} =$ $- 0.76$ V

$F e^{2 +} + 2 e^{-} \to F e;$ $E_{r e d}^{o} =$ $- 0.44$ V

Which of the following statement is correct ?

Q. The standard electrode potential of the half cells is given below:

Z n^{2 +} + 2 e^{-} \to Z n; E = - 0.76 V

F e^{2 +} + 2 e^{-} \to F e; E = - 0.44 V

The emf of the cell

F e^{2 +} = Z n^{-} \to Z n^{2 +} + F e

Given standard electrode potentials:

$F e^{3 +} + 3 e^{-} \to F e; E^{0} = - 0.036 V$

$F e^{2 +} + 2 e^{-} \to F e; E^{0} = - 0.440 V$

The standard electrode potential $E^{o}$ for $F e^{3 +} + e^{-} \to F e^{2 +}$ is:

$E^{\circ}$ value of $M g^{2 +} | M g, Z n^{2 +} | Z n$ and $F e^{2 +} | F e$ are – 2.37 V, - 0.76 V and 0.44 V respectively. Which of the following is correct?

Join BYJU'S Learning Program

Standard reduction potential values for the electrodes are given belowMg2++2e−→Mg; E0=−2.37VZn2++2e−→Zn; E0=−0.76VFe2++2e−→Fe; E0=−0.44VWhich of the following statements is correct?

The correct option is B Zinc will reduce Fe2+Zinc will reduce Fe2+ as zinc has more negative standard reduction potential than iron. More negative standard reduction potential means zinc is stronger reducing agent than iron.

Standard reduction potential values for the electrodes are given below
$M g^{2 +} + 2 e^{-} \to M g; E^{0} = - 2.37 V$
$Z n^{2 +} + 2 e^{-} \to Z n; E^{0} = - 0.76 V$
$F e^{2 +} + 2 e^{-} \to F e; E^{0} = - 0.44 V$
Which of the following statements is correct?

The correct option is B Zinc will reduce $F e^{2 +}$
$Z i n c$ will reduce $F e^{2 +}$ as zinc has more negative standard reduction potential than $i r o n$ . More negative standard reduction potential means $z i n c$ is stronger reducing agent than $i r o n$ .