Question

Standing eaves are produced in 10 m long stretched string fixed at both ends. If the string vibrates in 5 segments and wave velocity is 20 m/s, the frequency is

Answer 1

String is stretched both ends

frequency f = V/2L

where V is velocity

L is length of string

But it is divided into 5 segments

$f=\frac{5V}{2L}$

$=\frac{5\times 20}{2\times 10}$

$f=5Hz$