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Standard XII

Physics

Acceleration

Starting from...

Question

Starting from rest, a particle moves with a non-uniform acceleration. From the following acceleration-time graph, find the velocity of the particle at t = 10 s.

90 m/s

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75 m/s

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60 m/s

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45 m/s

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Solution

The correct option is D 45 m/s
$Δ$ v = Area under a-t graph
$\Rightarrow V - 0 = \frac{1}{2} \times (10 + 5) \times 6 \Rightarrow V = \frac{1}{2} \times 15 \times 6 = 45 m / s$

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Starting from rest, a particle moves with a non-uniform acceleration. From the following acceleration-time graph, find the velocity of the particle at t = 10 s.

The correct option is D 45 m/sΔ v = Area under a-t graph ⇒V−0=12×(10+5)×6⇒V=12×15×6=45m/s

The correct option is D 45 m/s
$Δ$ v = Area under a-t graph
$\Rightarrow V - 0 = \frac{1}{2} \times (10 + 5) \times 6 \Rightarrow V = \frac{1}{2} \times 15 \times 6 = 45 m / s$