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Standard XII

Physics

Displacement

Starting from...

Question

Starting from rest the acceleration of a particle is $a = 2 (t - 1)$ . The velocity of the particle at $t = 5 s$ is

15 m / s

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25 m / s

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5 m / s

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Solution

The correct option is A $15 m / s$
$v = \int_{0}^{5} a d t$

$v = \int_{0}^{5} 2 (t - 1) d t = [t^{2} - 2 t]_{0}^{5}$

$v = (5)^{2} - 2 (5) - (0)^{2} + 2 (0) = 15 m / s$

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Starting from rest the acceleration of a particle is a=2(t−1) . The velocity of the particle at t=5s is

The correct option is A 15 m/sv=∫50adtv=∫502(t−1)dt=[t2−2t]50v=(5)2−2(5)−(0)2+2(0)=15 m/s

Starting from rest the acceleration of a particle is $a = 2 (t - 1)$ . The velocity of the particle at $t = 5 s$ is

The correct option is A $15 m / s$
$v = \int_{0}^{5} a d t$

$v = \int_{0}^{5} 2 (t - 1) d t = [t^{2} - 2 t]_{0}^{5}$

$v = (5)^{2} - 2 (5) - (0)^{2} + 2 (0) = 15 m / s$