State true or false- a1-a2-a3 - -R then- a1-a2-a3 1a1- 1a2- 1a33- 27

The correct option is A TrueGiven, (a_1+a_2+a_3)(1/a_1+1/a_2+1/a_3)≤ 27 for a_1+a_2+a_3=1 then #160; (1+1+1)(1/1+1/1+1/1)≤ 27 (3)(1/3)^3≤ 27 ...

You visited us 43 times! Enjoying our articles? Unlock Full Access!

Definition of Functions

State true or...

Question

State true or false:
$a_{1}, a_{2}, a_{3} \in + R$ then, $(a_{1} + a_{2} + a_{3}) {(\frac{1}{a_{1}} + \frac{1}{a_{2}} + \frac{1}{a_{3}})}^{3} \leq 27$

True

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

False

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

a_{1}, a_{2}, a_{3} \in + R

\frac{a_{1}}{a_{2}} + \frac{a_{2}}{a_{3}} + \frac{a_{3}}{a_{1}} \geq 3

a_{1}, a_{2}, a_{3}, . . . . . . . . ., a_{n}

(a_{1} + a_{2} + a_{3} + . . . . . . . + a_{n}) (\frac{1}{a_{1}} + \frac{1}{a_{2}} + \frac{1}{a_{3}} . . . . . . . . . . . . + \frac{1}{a_{n}}) \geq n^{2}

a_{1}, a_{2}, a_{3} \in + R

3 a_{1} a_{2} a_{3} \leq a_{1}^{3} + a_{2}^{3} + a_{3}^{3}

n

a_{1}, a_{2}, a_{3}, . . . ., a_{n}

A

A = \frac{a_{1} + a_{2} + . . . . + a_{n}}{n}

a_{1}, a_{2}, a_{3}, . . . a_{n}

\frac{a_{1}}{a_{2} + a_{3} + . . . a_{n}}, \frac{a_{2}}{a_{1} + a_{3} + . . . a_{n}}, \frac{a_{3}}{a_{1} + a_{2} + a_{4} + . . . + a_{n}}, \frac{a_{n}}{a_{1} + a_{2} + . . . + a_{n}}

Join BYJU'S Learning Program