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Ammonia

State True or...

Question

State True or False.
Mercury(II) ions react with KI to form orange precipitate of $H g I_{2}$ which is soluble in excess of KI to form $K_{2} H g I_{4}$ .

True

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False

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Solution

The correct option is A True
$H g^{2 +} + 2 I^{-} \to H g I_{2} ↓$
Scarlet red ppt
The precipitate dissolves in excess reagent, when colourless tetraiodomecurate (II) ions are formed.
$H g I_{2} + 2 I^{-} ⟶ [H g I_{4}]^{2 -}$ or $H g l_{2} + 2 K I \to K_{2} [H g I_{4}]$
soluble
An alkaline solution of potassium teraiodomercurate (II) serves as a selective and sensitive reagent for ammonium ions ( Nessler's reagent )

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