State True or False- -2a2-2-6ab-3b2 - -2a-3b

The correct option is A True √(2a^2+2√(6)ab+3b^2)=√((√(2)a)^2+2× (√(2)a)× (√(3)b)+(√(3)b)^2) nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbs ...

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Identity - 1 (Irrational Numbers) 1

State True or...

Question

State True or False.
$\sqrt{2 a^{2} + 2 \sqrt{6} a b + 3 b^{2}} =$ $\sqrt{2} a + \sqrt{3} b$

True

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False

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Solution

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Similar questions

8 a^{3} + b^{3} + 12 a^{2} b + 6 a b^{2}

= (2 a + b) (2 a + b) (2 a + b)

8 a^{3} - b^{3} - 12 a^{2} b + 6 a b^{2}

= (2 a - b) (2 a - b) (2 a - b)

Factorize:

$2 a^{2} + 2 \sqrt{6} a b + 3 b^{2}$

4 a^{4} + 11 a^{2} b^{2} + 9 b^{4}

2 a^{2} - a b + 3 b^{2}

2 a^{2} + a b + 3 b^{2}

2 a^{2} + 2 \sqrt{6} a b + 3 b^{2}

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