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Question

State True or False.

a(b2c2) = (ab)(bc)(ca)

A
True
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B
False
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Solution

The correct option is A True
Consider, L.H.S. =Σa(b2c2)

=ab2ac2+bc2ba2+ca2cb2

adding and subracting abc,
abc+ab2ac2+bc2ba2+ca2cb2abc

=a(bcabc2+ac)b(bcabc2+ac)

=(ab)(bcabc2+ac)=(ab)(bc)(ca)


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