Question

State True or False.

The orbital angular momentum of a $p$ electron is equal to $\sqrt{2}$$\frac{h}{2\pi }$.

• A. True
• B. False

Answer 1

The correct option is A True

Angular momentum in an orbital $=\frac{h}{2\pi }\sqrt{l(l+1)}$

$l=0$ for s orbital, hence orbital angular momentum $=0$

$l=1$ for p orbital

$\therefore$ Angular momentum $=\frac{h}{2\pi }\sqrt{(1+1)\times 1}=\sqrt{2}\frac{h}{2\pi }$