Question

State True or False.

The orbital angular momentum of a s electron is equal to $\sqrt{2}$$\frac{h}{2\pi }$.

• A. True
• B. False

Answer 1

The correct option is B False

The orbital angular momentum of a s electron is equal to $\sqrt{l(l+1)}\frac{h}{2\pi }=\sqrt{0(0+1)}\frac{h}{2\pi }=0$
Since s orbital is spherical in shape, its orbital angular momentum is zero.