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Question

State whether each ordered pair of numbers shown is a solution of the given equation or not:
3x+y=6;(1,3),(2,0)

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Solution

3x+y=6;(1,3),(2,0)

3x+y=6;at(1,3)=3×1+3=3+3=6

Hence LHS=RHS

(1,3) is a solution of 3x+y=6

3x+y=6;at(2,0)=3×2+0=6+0=6

Hence LHS=RHS

(2,0) is a solution of 3x+y=6

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