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Question

State whether the statement is True or False.
(xaxb)1ab(xbxc)1bc(xcxa)1ca=1

A
True
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B
False
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Solution

The correct option is A True
L.H.S =(xaxb)1ab(xbxc)1bc(xcxa)1ca
=(xaabxbab)(xbbcxcbc)(xccaxaca)
=(x1bx1a)(x1cx1b)(x1ax1c)
=1
=R.H.S

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