Question

State whether the statement is True or False:

Expanding ${(3x-\frac{1}{3x})}^2$, we get $9x^2-2+\frac{1}{9x^2}$.

• A. True
• B. False

Answer 1

The correct option is A True

Given, $(3x-\frac{1}{3x}{)}^2$.

We know, $(a-b{)}^2=a^2-2ab+b^2$.

Then,

$(3x-\frac{1}{3x}{)}^2={\left(3x\right)}^2-2(3x\left)\right(\frac{1}{3x})+(\frac{1}{3x}{)}^2=9x^2-2+\frac{1}{{9x}^2}.$

Therefore, the statement is true.

Hence, option $A$ is correct.