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Question

Statement 1: KCl is more likely to show schottky defect while Lil is more likely to show Frenkel defect.
Statement 2: Schottky defect is more likely in ionic solids in which cations and anions are of comparable size while Frenkel defect is more likely is which cations and anions have large differences in their ionic sizes.

A
Statement-1 is true, Statement-2 is true and Statement-2 is correct explanation for Statement-1
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B
Statement-1 is true, Statement-2 is true and Statement-2 is not the correct explanation for Statement-1
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C
Statement-1 is true but Statement-2 is false
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D
Statement-1 is false but Statement-2 is true
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Solution

The correct option is A Statement-1 is true, Statement-2 is true and Statement-2 is correct explanation for Statement-1
In case of KCl, the cation and the anion are of comparable size while in case of LiI, the cation Li+ is very small as compared to the iodide ion, I-. Hence, KCl is more likely to show Schottky defect while LiI tends to show Frenkel defect. Thus, the statements 1 and 2 are true and 2 is correct explanation of 1.

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