Question

Statement - 1 : Nucleophilicity order in polar - protic solvent is $I^{-}<B{r}^{-}<C{l}^{-}<F^{-}$
Statement - 2 : Due to bigger size of $I^{-}$ it is less solvated in polar protic solvent.

• A. Statement - 1, is true, statement 2 is true and statement - 2 is correct explanation for statement - .1.
• B. Statement - 1, is true, statement 2 is true and statement - 2 is NOT the correct explanation for statement - .1.
• C. Statement - 1 is true, statement - 2 is false.
• D. Statement - 1 is false, statement - 2 is true.

Answer 1

Answer: (D)

Statement - 1 is false, statement - 2 is true.

The order of size of halide ions in polar protic solvent.

$I^{-}>B{r}^{-}>C{l}^{-}>F^{-}$

Due to greater size of $I^{-}$,the surface charge density is low,so it is less solvated in the polar protic solvent.Hence the order of nucleophilicity is

$I^{-}>B{r}^{-}>C{l}^{-}>F^{-}$