Statement - 1 : Work done by a force on a body whose centre of mass does not move may be non-zero.
Statement -2 : Work done by a force depends on the displacement of the centre of mass.

Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for statement-1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Statement-1 is True, Statement-2 is True; Statement-2 is not a correct explanation for statement-1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Statement-1 is True, Statement-2 is False

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Statement-1 is False, Statement-2 is True.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D Statement-1 is True, Statement-2 is False
Work is defined as force times the displacement of the point of application .
So work done depends on displacement of point of application of force and not on displacement of centre of mass. Hence statement-2 is false

Suggest Corrections

Similar questions

- 1 :

0 < x < y \Rightarrow {log}_{a} x > {log}_{a} y

a > 1

- 2 :

a > 1, {log}_{a} x

Statement 1: Force acting on a body increases its kinetic energy from 200 J to 400 J and the force does a positive work on the body.

Statement 2: A force does a positive work on an object when the displacement due to the force is in the direction of the force itself.

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} = (n + 2) 2^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} x^{r} = (1 + x)^{n} + n x (1 + x)^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} = (n + 2) 2^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} x^{r} = (1 + x)^{n} + n x (1 + x)^{n - 1} .

2 m g

Join BYJU'S Learning Program