Question

Statement-I: Iodination of alkanes is carried out in the presence of iodic acid.
Because
Statement-II: Iodic acid removes $I_2$ gas from the reaction mixture.

• A. Statement-I is True, Statement-II is True ; Statement-II is a correct explanation for Statement-I
• B. Statement-I is True, Statement-II is True ; Statement-II is NOT a correct explanation for Statement-I
• C. Statement-I is True, Statement-II is False
• D. Statement-I is False, Statement-II is True

Answer 1

Answer: (C)

Statement-I is True, Statement-II is False

Iodination of alkanes is carried out in the presence of iodic acid.

The iodination reaction is a reversible reaction.

HI is a strong reducing agent and it reduces alkyl iodide back to alkane.
$R-H+I_2\rightleftharpoons R-I+HI$

To prevent this, some oxidizing agents such as mercuric oxide (HgO), iodic acid ($HI{O}_3$) or dil. nitric acid

($HN{O}_3$) are used which decompose HI acid.

$5R-H+2I_2+HI{O}_3\to 5R-I+3H_{2}O$.

Hence the correct option is C.