Question

When 2-butyne reacts with triethylamine followed by Br₂​ then meso-2,3-dibromobutane is produced.

• A. True
• B. False

Answer 1

The correct option is B False

Reactions of 2-Butyne

1. 2-Butyne is partially reduced with sodium in liquid ammonia to obtain 2-Butene.
2. Reaction involved: $\underset{2-\mathrm{Butyne}}{{\mathrm{CH}}_3\mathrm{C}\equiv {\mathrm{CCH}}_3\left(\mathrm{l}\right)}+\underset{\mathrm{Sodium}\mathrm{in}\mathrm{liquid}\mathrm{ammonia}}{\mathrm{Na},\left({\mathrm{NH}}_3\right(\mathrm{l}\left)\right)}\to \underset{2-\mathrm{Butene}}{{\mathrm{CH}}_3\mathrm{CH}={\mathrm{CHCH}}_3\left(\mathrm{l}\right)}$
3. In 2-Butene when a molecule of dibromine is added then meso 2,3 dibromobutane is formed.
4. Reaction involved: $\underset{2-\mathrm{Butene}}{{\mathrm{CH}}_3\mathrm{CH}={\mathrm{CHCH}}_3\left(\mathrm{l}\right)}+\underset{\mathrm{Dibromine}}{{\mathrm{Br}}_2\left(\mathrm{g}\right)}\to \underset{\mathrm{Meso}2,3\mathrm{dibromo}\mathrm{butane}}{{\mathrm{CH}}_3\mathrm{CH}\left(\mathrm{Br}\right)-\mathrm{CH}\left(\mathrm{Br}\right){\mathrm{CH}}_3\left(\mathrm{s}\right)}$

Hence, in this way, meso 2,3 dibromoibutane is formed, and the above statement is false.