Question

Stationary waves are set up in air column. The velocity of sound in air is $330m/s$ and frequency is $165Hz.$ Then the distance between the nodes is

• A. $2m$
• B. $1m$
• C. $0.5m$
• D. $4m$

Answer 1

The correct option is B $1m$

$v=330m/s;n=165Hz$.
Distance between two successive nodes $=\frac{\lambda }{2}=\frac{v}{2n}$

$=\frac{330}{2\times 165}=1m$