Question

Stationary waves of frequency 300 Hz are formed in a medium in which the velocity of sound is $1200metre/sec$ . The distance between a node and the neighboring antinode is

• A. 1 m
• B. 2 m
• C. 3 m
• D. 4 m

Answer 1

The correct option is A

1 m

required distance $=\frac{\lambda }{4}=\frac{v/n}{4}=\frac{1200}{4\times 300}=1m$