Question

Stationary waves of frequency $300\text{Hz}$ are formed in a string, in which the velocity of wave is $200\text{m/s}$. The distance between a node and the consecutive antinode is

• A. $\frac{1}{6}\text{m}$
• B. $2\text{m}$
• C. $\frac{3}{2}\text{m}$
• D. $4\text{m}$

Answer 1

The correct option is A $\frac{1}{6}\text{m}$

Given, $f=300\text{Hz}$
Velocity of transverse wave is $v=f\lambda$
$\Rightarrow v=300\times \lambda$
$\Rightarrow 200=300\times \lambda$
$\therefore \lambda =\frac{2}{3}\text{m}$


Distance between a node and consecutive antinode is $\Delta x=\frac{\lambda }{4}$
$\therefore \Delta x=\frac{2}{12}=\frac{1}{6}\text{m}$.