Steam at 100∘C is passed into 1.1kg of water contained in a calorimeter of water equivalent 0.02kg at 15∘C till the temperature of the calorimeter and its contents rises to 80∘C. The mass of the steam condensed in kilograms is
A
0.130
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B
0.065
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C
0.260
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D
0.135
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Solution
The correct option is A0.130 Heat required, Q=(1.1+0.02)×103×1×(80−15)=72800cal Let m gram of steam is condensed, then heat loss =m×540+m×1×20 =560m Heat loss = Heat gain ⇒560m=72800 ⇒m=130g=0.130kg.