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Question

Steam at 100oC is passed into 1.1 kg of water contained in a calorimeter of water equivalent 0.02 kg at 15oC till the temperature of the calorimeter and its contents rises to 80oC. The mass of the steam condensed in kg is
(Latent heat of vapor = 540 cal/g)


A

0.130

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B

0.065

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C

0.260

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D

0.135

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Solution

The correct option is D

0.135


Heat required Q=(1.1+0.02) × 103 × 1 × (8015)=72800 cal.
Therefore, mass of steam condensed (in kg)
m=QL=72800540 × 103 = 0.135 kg.


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