You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XIII

Physics

Latent Heat

Steam at 100o...

Question

Steam at $100^{o} C$ is passed into 1.1 kg of water contained in a calorimeter of water equivalent 0.02 kg at $15^{o} C$ till the temperature of the calorimeter and its contents rises to $80^{o} C .$ The mass of the steam condensed in kg is

(IIT JEE 1986)

0.13

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.065

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.26

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.135

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D 0.135
Heat required $Q = (1.1 + 0.02) \times 10^{3} \times 1 \times (80 - 15) = 72800 c a l .$
Therefore, mass of steam condensed (in kg)
$m = \frac{Q}{L} = \frac{72800}{540} \times 10^{- 3} = 0.135 k g .$

Suggest Corrections

Similar questions

Q. Steam at

100^{o} C

is passed into 1.1 kg of water contained in a calorimeter of water equivalent 0.02 kg at

15^{o} C

till the temperature of the calorimeter and its contents rises to

80^{o} C .

The mass of the steam condensed in kg is

(IIT JEE 1986)

Q. Steam at

100^{o} C

is passed into 1.1 kg of water contained in a calorimeter of water equivalent 0.02 kg at

15^{o} C

till the temperature of the calorimeter and its contents rises to

80^{o} C .

The mass of the steam condensed in kg is

(IIT JEE 1986)

Q. Steam at

100^{\circ} C

is passed into

1.1

kg of water contained in a calorimeter of water equivalent

0.02

kg at

15^{\circ} C

till the temperature of the calorimeter and its contents rises to

80^{\circ} C

.The mass of the steam condensed in kg is

Q. Some steam at

100^{\circ} C

is passed into

1.1 k g

of water contained in a calorimeter of water equivalent

0.02 k g

15^{\circ} C

so that the temperature of the calorimeter and its contents rises to

80^{\circ} C

. What is the mass of steam condensing (in

k g

)

Q. Steam at

100^{\circ} C

is passed into 1.1 kg of water contained in a calorimeter of water equivalent 0.02 kg at

15^{\circ} C

till the temperature of the calorimeter and its contents rise at

80^{\circ} C

. The mass of the stem condensed in kilogram is

Join BYJU'S Learning Program

Steam at 100oC is passed into 1.1 kg of water contained in a calorimeter of water equivalent 0.02 kg at 15oC till the temperature of the calorimeter and its contents rises to 80oC. The mass of the steam condensed in kg is (IIT JEE 1986)

The correct option is D 0.135Heat required Q=(1.1+0.02) × 103 × 1 × (80−15)=72800 cal. Therefore, mass of steam condensed (in kg) m=QL=72800540 × 10−3=0.135kg.

Steam at $100^{o} C$ is passed into 1.1 kg of water contained in a calorimeter of water equivalent 0.02 kg at $15^{o} C$ till the temperature of the calorimeter and its contents rises to $80^{o} C .$ The mass of the steam condensed in kg is

(IIT JEE 1986)

The correct option is D 0.135
Heat required $Q = (1.1 + 0.02) \times 10^{3} \times 1 \times (80 - 15) = 72800 c a l .$
Therefore, mass of steam condensed (in kg)
$m = \frac{Q}{L} = \frac{72800}{540} \times 10^{- 3} = 0.135 k g .$