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Question
Steam at 100oC is passed into 1.1 kg of water contained in a calorimeter of water equivalent 0.02 kg at 15oC till the temperature of the calorimeter and its contents rises to 80oC. The mass of the steam condensed in kg is
latent heat of vaporization of water = 540 cal kg−1, specific heat capacity of water = 103 cal kg−1∘C−1
Steam at 100oC is passed into 1.1 kg of water contained in a calorimeter of water equivalent 0.02 kg at 15oC till the temperature of the calorimeter and its contents rises to 80oC. The mass of the steam condensed in kg is
latent heat of vaporization of water = 540 cal kg−1, specific heat capacity of water = 103 cal kg−1∘C−1
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Solution
The correct option is D 0.135
Heat required Q= (1.1+0.02) × 103 × 1 × (80−15)=72800 cal.
Therefore, mass of steam condensed (in kg)
m=QL=72800540 × 10−3=0.135kg.
0.135
Heat required Q= (1.1+0.02) × 103 × 1 × (80−15)=72800 cal.
Therefore, mass of steam condensed (in kg)
m=QL=72800540 × 10−3=0.135kg.
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