wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Steve saw 313 birds during a bird-watching trip to Yellowstone National Park. He observed 15 more trumpeter swans than sand-hill cranes. He saw twice as many mountain chickadees as dusky grouses. How many birds of each type did Steve observe if he saw half as many trumpeter swans as dusky grouses?


Open in App
Solution

Find how many birds of each type did Steve observe:

Step-1: Make the equations:

Total number of birds =313

Trumpeter swans =s

Sandhill cranes = c

Mountain chickadees = m

Ducky grouses = g

We have equations below based on given:

There are 15 more trumpeter swans than sand-hill cranes.

s=c+15

There are half as many trumpeter swans as dusky grouses.

g=2sg=2c+15

There are twice as many mountain chickadees as dusky grouses.

m=2g

m=22sm=4sm=4c+15s=c+15

Total number of birds. he visited is given as 313

s+c+m+g=313.

Step-2: Solve for c:

Substituting the value of m,g and s as above in s+c+m+g=313 and finding the value of c:

c+15+c+2c+15+4c+15=313

Now solve for c

8c+15+30+60=3138c+105=3138c=313-105subtracting105frombothsides8c=208

c=2088Dividing8frombothsides

c=26

Step-3: Calculate the other values:

Substitute value of c in s=c+15

s=26+15s=41

Substitute value of s in g=2s

g=2×41g=82

Substitute value of g in m=2g

m=2×82m=164

Hence, the answer is

Trumpeter swans =41

Sandhill cranes =26

Mountain chickadees =164

Ducky grouses =82


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Venn Diagrams
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon