Straight distance between a hotel and a railway station is 10 kms but circular route is followed by a taxi covering 23 kms in 28 mins. What is the average speed and magnitude of average velocity? Are they equal?

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Solution

Here,

Total distance traveled = 23 km

Total time taken = 28 min = 28/60 h

So, average speed = 23/(28/60) = 49.3 km/h

Total displacement is = 10 km

So, average velocity is = 10/(28/60) = 21.4 km/h

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Straight distance between a hotel and a railway station is 10 kms but circular route is followed by a taxi covering 23 kms in 28 mins. What is the average speed and magnitude of average velocity? Are they equal?

Here, Total distance traveled = 23 km Total time taken = 28 min = 28/60 h So, average speed = 23/(28/60) = 49.3 km/h Total displacement is = 10 km So, average velocity is = 10/(28/60) = 21.4 km/h

Here,

Total distance traveled = 23 km

Total time taken = 28 min = 28/60 h

So, average speed = 23/(28/60) = 49.3 km/h

Total displacement is = 10 km

So, average velocity is = 10/(28/60) = 21.4 km/h