Question

Strength of $H_2{O}_2$ is $15.18g{L}^{-1}$, then it is equal to:

• A. $1$ volume
• B. $10$ volume
• C. $5$ volume
• D. $7$ volume

Answer 1

The correct option is C $5$ volume

Strength of $H_2{O}_2$ is $15.18g/L$

$2H_2{O}_2\to 2H_{2}O+O_2$

$2(2+32)=68g$ and $22.4l$ of $O_2$

$\therefore 68g$ of $H_2{O}_2$ liberates $22.4l$ of $O_2$

and $15.18g$ of $H_2{O}_2$ liberates = $22.4\times 15.18/68$

$=5l$

Hence, the correct option is $C$