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Valence Bond Theory

Study the fol...

Question

Study the following thermochemical equations: The correct order of enthalpies of formation of A, B and C is
$A \to B$ ; $Δ H = + 100 K c a l$
$C \to B$ ; $Δ H = + 10 K c a l$

A < B < C

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A < C < B

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C < A < B

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B < C < A

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Solution

The correct option is B A < C < B
B has higher enthapy of 100Kcal from A and it has higher enthapy of 10kcal from C. so order is B > C > A.

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Similar questions

A \to B; Δ H = + 24 k J / m o l e

B \to C, Δ H = - 18 k J / m o l e

A, B, C

\frac{a {(b - c)}^{2}}{(c - a) (a - b)} + \frac{b {(c - a)}^{2}}{(a - b) (b - c)} + \frac{c {(a - b)}^{2}}{(b - c) (c - a)} = a + b + c

(Δ H_{f}^{o} H_{a q}^{+} = 0)

H_{2} O (l) \to H^{+} (a q) + O H^{-} (a q); Δ H = 57.32 k J

H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (l); Δ H = - 286.20 k J

O H^{-}

25^{o} C

a, b

c

Δ = ∣ ∣ ∣ ∣ \begin{matrix} b + c & c + a & a + b c + a & a + b & b + c a + b & b + c & c + a \end{matrix} ∣ ∣ ∣ ∣ = 0

a + b + c = 0

a = b = c

∣ ∣ ∣ ∣ ∣ \begin{matrix} b c - a^{2} & c a - b^{2} & a b - c^{2} - b c + c a + a b & b c - c a + a b & b c + c a - a b (a + b) (a + c) & (b + c) (b + a) & (c + a) (c + b) \end{matrix} ∣ ∣ ∣ ∣ ∣ = 3. (b - c) (c - a) (a - b) (a + b + c) (a b + b c + c a)

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$A \to B$ ;	$Δ H = + 100 K c a l$
$C \to B$ ;	$Δ H = + 10 K c a l$