Question

Study the Venn diagram given below and identify the compounds X, Y, and Z from the given options.

• A. X: $H_{2}S{O}_4$;
  Y: $C_{12}{H}_{22}{O}_{11}$;
  Z: $Ca(OH{)}_2$
• B. X: $HN{O}_3$;
  Y: $C_2{H}_{5}OH$;
  Z: $C{H}_{3}COONa$
  
• C. X: $Ca(OH{)}_2$;
  Y: HCOOH;
  Z: $C_{12}{H}_{2}6$
  
• D. X: $H_{2}S{O}_4$;
  Y: $C{H}_{3}COONa$;
  Z: $C_2{H}_{5}OH$
  

Answer 1

The correct option is B X: $HN{O}_3$;

Y: $C_2{H}_{5}OH$;
Z: $C{H}_{3}COONa$

Here in the Venn diagram , it is said that compound X contains only ions; compound Z has both ions and molecules and compound Y has only molecules and no ions.
We know that strong electrolytes has only ions; weak electrolytes has both ions and molecules and non-electrolytes has no ions.
Strong electrolytes: $NaCl,H_{2}S{O}_4,NaOH,Ca(OH{)}_2,HN{O}_3$.
Weak electrolytes: HCOOH and $C{H}_{3}COONa$.
Non-electrolytes: $C_2{H}_{5}OH$ and $C_6{H}_{12}{O}_6$ .

Therefore, the correct answer is option C.