Subtract: $- 2 x^{2} y + 3 x y^{2}$ from $8 x^{2} y$

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Solution

Simply Substracting $- 2 x^{2} y + 3 x y^{2}$ From $8 x^{2} y$ Hence $8 x^{2} y - (- 2 x^{2} y) + 3 x y^{2}$
= $8 x^{2} y + 2 x^{2} y + 3 x^{2} y$
= $13 x^{2} y$

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Question 60 (a)

What should be subtracted from $2 x^{3} - 3 x^{2} y + 2 x y^{2} + 3 y^{3}$ to get $x^{3} - 2 x^{2} y + 3 x y^{2} + 4 y^{3} ?$

{2 x}^{2} y - {3 x y}^{2} + {2 x}^{2} y - {4 x}^{2} y + {2 x y}^{2}

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