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Question

Subtract 3k(5k−l−3m) from 6k(2k+3l−2m)

A
3k2+21kl3km
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B
4k2+21kl3km
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C
3k221kl3km
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D
None of these
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Solution

The correct option is A 3k2+21kl3km
We find the subtraction of the given polynomials 3k(5kl3m),6k(2k+3l2m) by combining the like terms as shown below:

6k(2k+3l2m)3k(5kl3m)=12k2+18kl12km15k2+3kl+9km=(12k215k2)+(18kl+3kl)+(12km+9km)=k2(1215)+kl(18+3)+km(12+9)=3k2+21kl3km

Hence, 6k(2k+3l2m)3k(5kl3m)=3k2+21kl3km.

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