Subtract: $a - b - 2 c$ from $4 a + 6 b - 2 c$ .

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Solution

Given: Subtract $a - b - 2 c$ and $4 a + 6 b - 2 c$
Getting the terms together and subtracting them for $(4 a + 6 b - 2 c) - (a - b - 2 c)$
$(4 a - a) + (6 b + b) + (- 2 c + 2 c)$
Hence $(4 a + 6 b - 2 c) - (a - b - 2 c) =$ $3 a + 7 b$

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Similar questions

Q. State True or False:
On subtracting

a - b - 2 c

from

4 a + 6 b - 2 c

, the answer is

3 a + 7 b

Q. Subtract: [2 MARKS]

(i)

3 a - 4 b + 5 c

from

4 a - b + 6 c

(ii)

5 a - 3 b + 2 c

from

a - 4 b - 2 c

From the sum of 7a – 2b + 11 and -2a -5, subtract 7a – b + 4.

Q. Subtract the sum of

a + 2 b - 3 c

and

2 c - 3 b - 4 a

from the sum of

5 b - 4 c + a

and

2 c - 3 b - 4 a

Tick $(✓)$ the correct answer in each of the following:
The sum of $(6 a + 4 b - c + 3), (2 b - 3 c + 4, (11 b - 7 a + 2 c - 1))$ and $(2 c - 5 a - 6)$ is

(a) $(4 a - 6 b + 2)$
(b) $(- 3 a + 14 b - 3 c + 2)$
(c) $(- 6 a + 17)$
(d) $(- 6 a + 6 b + c - 4)$

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Subtract: a−b−2c from 4a+6b−2c.

Given: Subtract a−b−2c and 4a+6b−2cGetting the terms together and subtracting them for (4a+6b−2c)−(a−b−2c)(4a−a)+(6b+b)+(−2c+2c)Hence (4a+6b−2c)−(a−b−2c)= 3a+7b

Subtract: $a - b - 2 c$ from $4 a + 6 b - 2 c$ .

Given: Subtract $a - b - 2 c$ and $4 a + 6 b - 2 c$
Getting the terms together and subtracting them for $(4 a + 6 b - 2 c) - (a - b - 2 c)$
$(4 a - a) + (6 b + b) + (- 2 c + 2 c)$
Hence $(4 a + 6 b - 2 c) - (a - b - 2 c) =$ $3 a + 7 b$