Subtract the sum of $a + 2 b - 3 c$ and $2 c - 3 b - 4 a$ from the sum of $5 b - 4 c + a$ and $2 c - 3 b - 4 a$ .

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Solution

$5 b - 4 c + a + 2 c - 3 b - 4 a = - 2 c + 2 b - 3 a$
$a + 2 b - 3 c + 2 c - 3 b - 4 a = - 3 s - b - c$
$(- 2 c + 2 b - 3 s) - (- 3 a - b - c)$
$- 2 c + 2 b - 3 a + 3 a + b + c$
$= 3 b - c$

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