Subtract p-2q+r from the sum of 10p-rand 5p+2q
Given that: Subtract p-2q+r from the sum of 10p-rand 5p+2q
Subtracting p-2q+r from the sum of 10p-rand 5p+2q:
Step 1: Sum of 10p-rand 5p+2q
=10p-r+5p+2q
=10p+5p-r+2q=15p-r+2q
Step 2: Subtracting p-2q+r from 15p-r+2q
=15p-r+2q-(p-2q+r)
=15p-r+2q-p+2q-r
=15p-p+2q+2q-r-r
=14p+4q-2r
Therefore, we get 14p+4q-2r.
Solve the following equations:
(a) 10p = 100 (b) 10p + 10 = 100 (c)
(d) (e) (f) 3s = − 9
(g) 3s + 12 = 0 (h) 3s = 0 (i) 2q = 6
(j) 2q − 6 = 0 (k) 2q + 6 = 0 (l) 2q + 6 = 12