Subtract the following: $(14 a^{3} b - 10 b^{2} - 28 a) {from(20a}^{3} {b+11b}^{2} +15a)$

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Solution

Finding the subtraction of algebraic expression
We find the subtraction of algebraic expression by the horizontal method
${(20a}^{3} {b+11b}^{2} +15a)- (14 a^{3} b - 10 b^{2} - 28 a) = 20 a^{3} {b+11b}^{2} +15a- 14 a^{3} b + 10 b^{2} + 28 a = 20 a^{3} b - 14 a^{3} b + 11 b^{2} + 10 b^{2} + 15 a + 28 a = 6 a^{3} b + 21 b^{2} + 43 a$
Hence, the subtraction of an algebraic expression is $6 a^{3} b + 21 b^{2} + 43 a$ .

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\begin{matrix} C & B & 5 \\ - & 2 & 8 & A \end{matrix} \begin{matrix} 2 & 5 & 9 \end{matrix}

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