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Question

Question 71

Subtract the sum of 12ab10b218a2 and 9ab+12b2+14a2 from the sum of ab+2b2 and 3b2a2.

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Solution

Sum of 12ab10b218a2 and 9ab+12b2+14a2
=12ab10b218a2+9ab+12b2+14a2
On combining the like terms,
=12ab+9ab10b2+12b218a2+14a2=21ab+2b24a2
Sum of ab+2b2 and 3b2a2
=ab+2b2+3b2a2=ab+5b2a2
Now, subtracting 21ab+2b24a2 from ab+5b2a2, we get
=(ab+5b2a2)(21ab+2b24a2)=ab+5b2a221ab2b2+4a2
On combining the like terms,
=ab21ab+5b22b2a2+4a2=20ab+3b2+3a2=3a2+3b220ab


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