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Question

Subtract the sum of 9b2+3c2 and 2b2+bc+2c2 from the sum of 2b2−2bc−c2 and c2+2bc−b2.

A
13b25bc+5c2
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B
10b2bc5c2
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C
10b2+bc5c2
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D
10b25bc5c2
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Solution

The correct option is B 10b2bc5c2
According to the question,
{(2b22bcc2)+(c2+2bcb2)}{(9b2+3c2)+(2b2+bc+2c2)}
={(2b2b2)+(2bc+2bc)+(c2c2)}{(9b2+2b2)+(3c2+2c2)+bc}
=(b2)(11b2+5c2+bc)
=b211b25c2bc
=10b2bc5c2.

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