Subtract the sum of 3l-4m-7nsquare and 2l+3m-4nsquare from the sum of 9l+2m-3nsquare and -3l+m+4nsquare

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Solution

Dear student
$We have, 9 l + 2 m - 3 n^{2} - 3 l + m + 4 n^{2} - [3 l - 4 m - 7 n^{2} + 2 l + 3 m - 4 n^{2}] = 6 l + 3 m + n^{2} - (5 l - m - 11 n^{2}) = 6 l + 3 m + n^{2} - 5 l + m + 11 n^{2} = l + 4 m + 12 n^{2}$
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