Question

Subtract the sum of-5/8 and 7/10 from the sum of 3/-5 and 8/15

Answer 1

Dear student
$$\begin{gathered} \mathrm{Sum}\mathrm{of}-\frac{5}{8}\mathrm{and}\frac{7}{10}=-\frac{5}{8}+\frac{7}{10}=\frac{-\left(5\times 5\right)+\left(7\times 4\right)}{40}=\frac{-25+28}{40}=\frac{3}{40}...\left(1\right) \\ \mathrm{Sum}\mathrm{of}\frac{3}{-5}\mathrm{and}\frac{8}{15}=\frac{3}{-5}+\frac{8}{15}=\frac{-(3\times 3)+(8\times 1)}{15}=\frac{-9+8}{15}=-\frac{1}{15}...\left(2\right) \\ \mathrm{Now},\mathrm{Subtract}\left(1\right)\mathrm{from}\left(2\right),\mathrm{we}\mathrm{get} \\ -\frac{1}{15}-\frac{3}{40} \\ =\frac{-(1\times 8)-(3\times 3)}{120} \\ =\frac{-8-9}{120} \\ =\frac{-17}{120} \end{gathered}$$
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