Question

Subtract the sum of (8a − 6a² + 9) and (−10a − 8 + 8a²) from −3.

Answer 1

(8a − 6a² + 9)+ (−10a − 8 + 8a²)

Collecting like terms and adding them:

$$\begin{gathered} 8\mathrm{a}-10\mathrm{a}-6{\mathrm{a}}^2+8{\mathrm{a}}^2+9-8 \\ =-2\mathrm{a}+2{\mathrm{a}}^2+1 \\ \mathrm{Now},-3-(-2\mathrm{a}+2{\mathrm{a}}^2+1) \\ =2\mathrm{a}-2{\mathrm{a}}^2-4 \end{gathered}$$