Question

Subtract the sum of (8m − 7n + 6p²) and (−3m − 4n − p²) from the sum of (2m + 4n − 3p²) and (− m − n − p²).

Answer 1

(8m − 7n + 6p²) + (−3m − 4n − p²)
$$\begin{gathered} =8\mathrm{m}-3\mathrm{m}-7\mathrm{n}-4\mathrm{n}+6{\mathrm{p}}^2-\mathrm{p}{}^2 \\ =5\mathrm{m}-11\mathrm{n}+5{\mathrm{p}}^2 \end{gathered}$$

(2m + 4n − 3p²) + (− m − n − p²).
$$\begin{gathered} =2\mathrm{m}-\mathrm{m}+4\mathrm{n}-\mathrm{n}-3{\mathrm{p}}^2-{\mathrm{p}}^2 \\ =\mathrm{m}+3\mathrm{n}-4{\mathrm{p}}^2 \end{gathered}$$


$$\begin{gathered} \mathrm{Now},(\mathrm{m}+3\mathrm{n}-4{\mathrm{p}}^2)-(5\mathrm{m}-11\mathrm{n}+5{\mathrm{p}}^2) \\ =-4\mathrm{m}+14\mathrm{n}-9{\mathrm{p}}^2 \end{gathered}$$