Subtract the sum of $3 l - 4 m - 7 n^{2}$ and $2 l + 3 m - 4 n^{2}$ from the sum of $9 l + 2 m - 3 n^{2}$ and $- 3 l + m + 4 n^{2}$ .

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Solution

$S u m o f 9 l + 2 m - 3 n^{2} a n d - 3 l + m + 4 n^{2} = 9 l + 2 m - 3 n^{2} + (- 3 l) + m + 4 n^{2} = 9 l + 2 m - 3 n^{2} - 3 l + m + 4 n^{2} = 9 l - 3 l + 2 m + m - 3 n^{2} + 4 n^{2} = 6 l + 3 m + n^{2} a n d s u m o f 3 l - 4 m - 7 n^{2} a n d 2 l + 3 m - 4 n^{2} = 3 l - 4 m - 7 n^{2} + 2 l + 3 m - 4 n^{2} = 3 l + 2 l - 4 m + 3 m - 7 n^{2} - 4 n^{2} = 5 l - m - 11 n^{2} N o w (6 l + 3 m + n^{2}) - (5 l - m - 11 n^{2}) = 6 l + 3 m + n^{2} - 5 l + m + 11 n^{2} = 6 l - 5 l + 3 m + m + n^{2} + 11 n^{2} = l + 4 m + 12 n^{2}$

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