Successive emission of - and 2 -particles results in the formation of isotopes- If true enter 1- else enter 0-

The reaction showing the emission of one alpha and two beta particles is as follows: _AX^M → _A 2X^M 4 + α→ _AX^M 4 + 2 β As reactant and product have same ...

You visited us 3 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Beta Decay

Successive em...

Question

Successive emission of $α$ - and 2 $β$ -particles results in the formation of isotopes. If true enter 1, else enter 0.

Open in App

Solution

The reaction showing the emission of one alpha and two beta particles is as follows:
$_{A} X^{M} \to_{A - 2} X^{M - 4} + α \to_{A} X^{M - 4} + 2 β$
As reactant and product have same same atomic number but different atomic masses, they are isotopes.
Hence, the given statement is correct.

Suggest Corrections

Similar questions

Q. Emission of one

α

- and two

β

-particles will result in the formation of an isotope.
If true enter 1, else enter 0.

Q. Both

α

and

β

-particles are emitted in a radioactive decay series.

If true enter 1, else enter 0.

Q. Successive emission of an

α

-particle and two

β

-particles by an atom of a radioactive element results in the formation of its:

Q. Charge on

α

-particles is

X +, X

is two. If true enter 1, else enter 0.

Q. If

\frac{x}{tan (θ + α)} = \frac{y}{tan (θ + β)} = \frac{z}{tan (θ + γ)},

then

\sum \frac{x + y}{x - y} {sin}^{2} (α - β) = 0

. If this is true enter 1, else enter 0.

Join BYJU'S Learning Program

Successive emission of α- and 2β-particles results in the formation of isotopes. If true enter 1, else enter 0.

The reaction showing the emission of one alpha and two beta particles is as follows:AXM→A−2XM−4+α→AXM−4+2βAs reactant and product have same same atomic number but different atomic masses, they are isotopes.Hence, the given statement is correct.

Successive emission of $α$ - and 2 $β$ -particles results in the formation of isotopes. If true enter 1, else enter 0.

The reaction showing the emission of one alpha and two beta particles is as follows:
$_{A} X^{M} \to_{A - 2} X^{M - 4} + α \to_{A} X^{M - 4} + 2 β$
As reactant and product have same same atomic number but different atomic masses, they are isotopes.
Hence, the given statement is correct.