Successive emission of - and 2 -particles results in the formation of isotopes- If true enter 1- else enter 0-

The reaction showing the emission of one alpha and two beta particles is as follows: _AX^M → _A 2X^M 4 + α→ _AX^M 4 + 2 β As reactant and product have same ...

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Standard XII

Chemistry

Beta Decay

Successive em...

Question

Successive emission of $α$ - and 2 $β$ -particles results in the formation of isotopes. If true enter 1, else enter 0.

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Solution

The reaction showing the emission of one alpha and two beta particles is as follows:
$_{A} X^{M} \to_{A - 2} X^{M - 4} + α \to_{A} X^{M - 4} + 2 β$
As reactant and product have same same atomic number but different atomic masses, they are isotopes.
Hence, the given statement is correct.

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Successive emission of α- and 2β-particles results in the formation of isotopes. If true enter 1, else enter 0.

The reaction showing the emission of one alpha and two beta particles is as follows:AXM→A−2XM−4+α→AXM−4+2βAs reactant and product have same same atomic number but different atomic masses, they are isotopes.Hence, the given statement is correct.

Successive emission of $α$ - and 2 $β$ -particles results in the formation of isotopes. If true enter 1, else enter 0.

The reaction showing the emission of one alpha and two beta particles is as follows:
$_{A} X^{M} \to_{A - 2} X^{M - 4} + α \to_{A} X^{M - 4} + 2 β$
As reactant and product have same same atomic number but different atomic masses, they are isotopes.
Hence, the given statement is correct.