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Question

Successive emission of an α-particle and two β-particles by an atom of a radioactive element results in the formation of its:

A
isobar
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B
isomer
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C
isotone
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D
isotope
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Solution

The correct option is D isotope
α-decay
AZXA4Z2Y+α
β-decay
AZXAZ+1Y+β
Successive emission of 1α and 2β particles will eventually cause no change in the atomic number of the daughter nuclei.
Hence, the daughter nuclei is an isotope of the present nuclei.

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